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2y^2-11y=22
We move all terms to the left:
2y^2-11y-(22)=0
a = 2; b = -11; c = -22;
Δ = b2-4ac
Δ = -112-4·2·(-22)
Δ = 297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{297}=\sqrt{9*33}=\sqrt{9}*\sqrt{33}=3\sqrt{33}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-3\sqrt{33}}{2*2}=\frac{11-3\sqrt{33}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+3\sqrt{33}}{2*2}=\frac{11+3\sqrt{33}}{4} $
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